=====Правый знак минус=====

^ Номер      ^  Условие                                                                                         ^  Ответ                                                                                                               ^
|    \\ 1.  |  \\ $(x-3)(2-x)\leqslant0$\\                                                             |  \\  $(-\infty; 2]\cup[3; +\infty)$                                                                                    |
|    \\ 2.  |  \\ $(x+3)(4-x)(5-x)(1-x)<0$\\                                                           |  \\  $(-\infty; -3)\cup(1; 4)\cup(5; +\infty)$                                                                       |
|  \\ 3.    |  \\ $(-x^2-7)(5x-7)>0$\\                                                                       |  \\  $\left(-\infty; \dfrac{7}{5}\right)$                                                                             |
|  \\ 4.    |  \\ $\dfrac{x-6}{7-x}\geqslant0$\\                                                             |  \\  $[6; 7)$                                                                                                         |
|  \\ 5.    |  \\ $\dfrac{6x-x^2}{x+1}>0$\\                                                                  |  \\  $(-\infty; -1)\cup(0; 6)$                                                                                        |
|  \\ 6.    |  \\ $\dfrac{7x^5-x^4}{4-x^2}<0$\\                                                              |  \\  $(-2; 0)\cup\left(0; \dfrac{1}{7}\right)\cup(2; +\infty)$                                                        |
|  \\ 7.    |  \\ $(3-x-2x^2)(x^2-5x+4)\leqslant0$\\                                                         |  \\  $\left(-\infty; -\dfrac{3}{2}\right]\cup\{1\}\cup[4; +\infty)$\\                                              |
|  \\ 8.    |  \\ $\dfrac{x-1}{x-2}-\dfrac{3x-1}{x-4}<0$\\                                                   |  \\  $\left(-\infty; \dfrac{1-\sqrt{5}}{2}\right)\cup\left(\dfrac{1+\sqrt{5}}{2}; 2\right)\cup(4; +\infty)$           |
|  \\ 9.    |  \\ $\dfrac{2-x}{3-x}-\dfrac{7x+5}{x+2}<\dfrac{4x+17}{x^2-x-6}$\\                              |  \\  $(-\infty; -2)\cup(3; +\infty)$                                                                                  |
|  \\ 10.   |  \\ $(x-1)^2-(x^2-3x-2)^2<0$\\                                                                 |  \\  $(-\infty; -1)\cup(2-\sqrt{5}; 3)\cup(2+\sqrt{5}; +\infty)$                                                      |
|  \\ 11.   |  \\ $\dfrac{1}{x-x^2+2}-\dfrac{2}{6-7x+x^2}\leqslant0$\\                                       |  \\ $(-\infty;-1)\cup\left[\dfrac{9-\sqrt{57}}{6};1\right)\cup\left(2; \dfrac{9+\sqrt{57}}{6}\right]\cup(6;+\infty)$  |
|  \\ 12.   |  \\ $\dfrac{x}{5x-3x^2-2}+\dfrac{x}{1+2x+3x^2}<0$\\                                            |  \\  $(-\infty; 0)\cup\left(\dfrac{1}{7}; \dfrac{2}{3}\right)\cup(1; +\infty)$                                        |
|  \\ 13.   |  \\ $\dfrac{3}{x}-\dfrac{x}{x^2+2x-3}<\dfrac{2}{x-1}$\\                                        |  \\  $(-3, 0)\cup(1, +\infty)$                                                                                        |
|  \\ 14.   |  \\ $\dfrac{9-x}{1+2x}-\dfrac{x}{2-5x}>0$\\                                                    |  \\  $\left(-\dfrac{1}{2}; 8-\sqrt{58}\right)\cup\left(\dfrac{2}{5}; 8+\sqrt{58}\right)$                              |
|  \\ 15.   |  \\ $\dfrac{1}{x^2+25}-\dfrac{1}{x-5}+\dfrac{1}{x+5}>0$\\                                      |  \\  $(-5; 5)$                                                                                                        |
|  \\ 16.   |  \\ $\dfrac{(x^2-3x)^2-(3x^2+6x)^2}{(16x^2+24x+9)^2}\geqslant0$\\                              |  \\  $\left[-\dfrac{9}{2}, -\dfrac{3}{4}\right)\cup\{0\}$                                                             |
|  \\ 17.   |  \\ $\dfrac{(x-37-x^2)(x^2-13x+30)}{(10-x)(1-x)}\geqslant0$\\                                  |  \\  $(1;3]$                                                                                                          |
|  \\ 18.   |  \\             $\dfrac{1}{2x^2-x-1}-\dfrac{1}{x^2-5x+4}<\dfrac{1}{5-2x^2-3x}$            \\   |  \\  $\left(-\dfrac{5}{2}; -\dfrac{29}{22}\right)\cup\left(-\dfrac{1}{2}; 1\right)\cup(4; +\infty)$                   |
|  \\ 19.   |  \\ $\dfrac{(4-x)^2(2-x)^3(21-x)}{(7-x)(-x-1)(-2x+5)}\geqslant0$\\                             |  \\  $(-\infty; -1)\cup\left[2; \dfrac{5}{2}\right)\cup\{4\}\cup(7; 21]$                                              |
|  \\ 20.   |  \\ $\dfrac{(x-4)^2(2-5x)^9(2-3x)^8}{(12+x)^4(x-1)^3(-2x+9)^8}\geqslant0$\\                    |  \\  $\left[\dfrac{2}{5}; 1\right)\cup\{4\}$                                                                          |