math-public:trigformulytest3
Различия
Показаны различия между двумя версиями страницы.
| Следующая версия | Предыдущая версия | ||
| math-public:trigformulytest3 [2018/04/04 23:55] – создано labreslav | math-public:trigformulytest3 [2018/04/06 10:49] (текущий) – labreslav | ||
|---|---|---|---|
| Строка 1: | Строка 1: | ||
| - | $\DeclareMathOperator{\tg}{tg}$ | + | $\DeclareMathOperator{\tg}{tg}$ $\DeclareMathOperator{\ctg}{ctg}$ |
| - | $\DeclareMathOperator{\ctg}{ctg}$ | + | |
| + | - $\tg^2{x}+1$ | ||
| + | - $\ctg^2{x}+1$ | ||
| + | - $2\sin{x}\cos{x}$ | ||
| + | - Три формулы $\cos^2{x}-\sin^2{x}$ | ||
| + | - $3\sin{x}-4\sin^3{x}$ | ||
| + | - $4\cos^3{x}-3\cos{x}$ | ||
| + | - $\dfrac{2\tg{x}}{1-\tg^2{x}}$ | ||
| + | - $\sin{x}\cos{y}+\cos{x}\sin{y}$ | ||
| + | - $\sin{x}\cos{y}-\cos{x}\sin{y}$ | ||
| + | - $\cos{x}\cos{y}-\sin{x}\sin{y}$ | ||
| + | - $\cos{x}\cos{y}+\sin{x}\sin{y}$ | ||
| + | - $\dfrac{\tg{x}+\tg{y}}{1-\tg{x}\tg{y}}$ | ||
| + | - $\dfrac{\tg{x}-\tg{y}}{1+\tg{x}\tg{y}}$ | ||
| + | - $\dfrac{1-\cos{2x}}{2}$ | ||
| + | - $\dfrac{1+\cos{2x}}{2}$ | ||
| + | - $\dfrac{2\tg{\dfrac{x}{2}}}{ 1+\tg^2{\dfrac{x}{2}}}$ | ||
| + | - $\dfrac{1-\tg^2{\dfrac{x}{2}}}{1+\tg^2{\dfrac{x}{2}}}$ | ||
| + | - $2\cos{\dfrac{x+y}{2}}\cos{\dfrac{x-y}{2}}$ | ||
| + | - $-2\sin{\dfrac{x+y}{2}}\sin{\dfrac{x-y}{2}}$ | ||
| + | - $2\sin{\dfrac{x+y}{2}}\cos{\dfrac{x-y}{2}}$ | ||
| + | - $2\sin{\dfrac{x-y}{2}}\cos{\dfrac{x+y}{2}}$ | ||
| + | - $\dfrac{1}{2}(\cos{(x-y)}+\cos{(x+y)})$ | ||
| + | - $\dfrac{1}{2}(\cos{(x-y)}-\cos{(x+y)})$ | ||
| + | - $\dfrac{1}{2}(\sin{(x-y)}+\sin{(x+y)})$ | ||
| - | - $\sin{2x} = 2\sin{x}\cos{x}$ | ||
| - | - Три формулы $\cos{2x}=\cos^2{x}-\sin^2{x}$ | ||
| - | - $\sin{3x}=3\sin{x}-4\sin^3{x}$ | ||
| - | - $\cos{3x}=4\cos^3{x}-3\cos{x}$ | ||
| - | - $\tg{2x}=\dfrac{2\tg{x}}{1-\tg^2{x}}$ | ||
| - | - $\sin{(x+y)}=\sin{x}\cos{y}+\cos{x}\sin{y}$ | ||
| - | - $\sin{(x-y)}=\sin{x}\cos{y}-\cos{x}\sin{y}$ | ||
| - | - $\cos{(x+y)}=\cos{x}\cos{y}-\sin{x}\sin{y}$ | ||
| - | - $\cos{(x-y)}=\cos{x}\cos{y}+\sin{x}\sin{y}$ | ||
| - | - $\tg{(x+y)}=\dfrac{\tg{x}+\tg{y}}{1-\tg{x}\tg{y}}$ | ||
| - | - $\tg{(x-y)}=\dfrac{\tg{x}-\tg{y}}{1+\tg{x}\tg{y}}$ | ||
| - | - $\sin^2{x}=\dfrac{1-\cos{2x}}{2}$ | ||
| - | - $\cos^2{x}=\dfrac{1+\cos{2x}}{2}$ | ||
| - | - Универсальная подстановка $\sin{x}=\dfrac{2\tg{\dfrac{x}{2}}}{ 1+\tg^2{\dfrac{x}{2}}}$ | ||
| - | - Универсальная подстановка $\cos{x}=\dfrac{1-\tg^2{\dfrac{x}{2}}}{1+\tg^2{\dfrac{x}{2}}}$ | ||
| - | - $\cos{x}+\cos{y}=2\cos{\dfrac{x+y}{2}}\cos{\dfrac{x-y}{2}}$ | ||
| - | - $\cos{x}-\cos{y}=-2\sin{\dfrac{x+y}{2}}\sin{\dfrac{x-y}{2}}$ | ||
| - | - $\sin{x}+\sin{y}=2\sin{\dfrac{x+y}{2}}\cos{\dfrac{x-y}{2}}$ | ||
| - | - $\sin{x}-\sin{y}=2\sin{\dfrac{x-y}{2}}\cos{\dfrac{x+y}{2}}$ | ||
| - | - $\cos{x}\cos{y}=\dfrac{1}{2}(\cos{(x-y)}+\cos{(x+y)})$ | ||
| - | - $\sin{x}\sin{y}=\dfrac{1}{2}(\cos{(x-y)}-\cos{(x+y)})$ | ||
| - | - $\sin{x}\cos{y}=\dfrac{1}{2}(\sin{(x-y)}+\sin{(x+y)})$ | ||
| - | - $\dfrac{1}{\cos^2{x}}=\tg^2{x}+1$ | ||
| - | - $\dfrac{1}{\sin^2{x}}=\ctg^2{x}+1$ | ||
| - | - $\sin{(\pi-x)}$ | ||
| - | - $\sin{(\pi+x)}$ | ||
| - | - $\sin{\left(\dfrac{\pi}{2}-x\right)}$ | ||
| - | - $\sin{\left(\dfrac{\pi}{2}+x\right)}$ | ||
| - | - $\sin{\left(\dfrac{3\pi}{2}-x\right)}$ | ||
| - | - $\sin{\left(\dfrac{3\pi}{2}+x\right)}$ | ||
| - | - $\sin{(-x)}$ | ||
| - | - $\cos{(\pi-x)}$ | ||
| - | - $\cos{(\pi+x)}$ | ||
| - | - $\cos{\left(\dfrac{\pi}{2}-x\right)}$ | ||
| - | - $\cos{\left(\dfrac{\pi}{2}+x\right)}$ | ||
| - | - $\cos{\left(\dfrac{3\pi}{2}-x\right)}$ | ||
| - | - $\cos{\left(\dfrac{3\pi}{2}+x\right)}$ | ||
| - | - $\cos{(-x)}$ | ||
| - | - $\tg{(\pi-x)}$ | ||
| - | - $\tg{(\pi+x)}$ | ||
| - | - $\tg{\left(\dfrac{\pi}{2}-x\right)}$ | ||
| - | - $\tg{\left(\dfrac{\pi}{2}+x\right)}$ | ||
| - | - $\tg{\left(\dfrac{3\pi}{2}-x\right)}$ | ||
| - | - $\tg{\left(\dfrac{3\pi}{2}+x\right)}$ | ||
| - | - $\tg{(-x)}$ | ||
| - | - $\ctg{(\pi-x)}$ | ||
| - | - $\ctg{(\pi+x)}$ | ||
| - | - $\ctg{\left(\dfrac{\pi}{2}-x\right)}$ | ||
| - | - $\ctg{\left(\dfrac{\pi}{2}+x\right)}$ | ||
| - | - $\ctg{\left(\dfrac{3\pi}{2}-x\right)}$ | ||
| - | - $\ctg{\left(\dfrac{3\pi}{2}+x\right)}$ | ||
| - | - $\ctg{(-x)}$ | ||
math-public/trigformulytest3.1522875340.txt.gz · Последнее изменение: 2018/04/04 23:55 — labreslav