Предыдущая версия справа и слеваПредыдущая версия | Следующая версияСледующая версия справа и слева |
math-public:up_s_b_bez_otvetov [2020/01/17 11:10] – labreslav | math-public:up_s_b_bez_otvetov [2020/01/17 11:14] – labreslav |
---|
| \\ 48. (2.052 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-x^2}}+1+\dfrac{1}{\dfrac{1}{\sqrt{1-x^2}}-1}\right)^{-2}:(2-x^2-2\sqrt{1-x^2}) $\\ | | | \\ 48. (2.052 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-x^2}}+1+\dfrac{1}{\dfrac{1}{\sqrt{1-x^2}}-1}\right)^{-2}:(2-x^2-2\sqrt{1-x^2}) $\\ | |
| \\ 49. (2.053 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-p^2}}-\sqrt{1+p^2}\right)^2+\dfrac{2}{\sqrt{1-p^4}} $\\ | | | \\ 49. (2.053 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-p^2}}-\sqrt{1+p^2}\right)^2+\dfrac{2}{\sqrt{1-p^4}} $\\ | |
| \\ 50. (2.071 Сканави) | \\ $\dfrac{(m-1)\sqrt{m}-(n-1)\sqrt{n}}{m^2\sqrt{mn}+mn+m^2-m} $\\ | | | \\ 50. (2.071 Сканави) | \\ $\dfrac{(m-1)\sqrt{m}-(n-1)\sqrt{n}}{\sqrt{m^3n}+mn+m^2-m} $\\ | |
| \\ 51. (2.079 Сканави) | \\ $\left(\sqrt{\sqrt{m}-\sqrt{\dfrac{m^2-9}{m}}}+\sqrt{\sqrt{m}+\sqrt{\dfrac{m^2-9}{m}}}\right)^2\sqrt{\sqrt{\dfrac{m^2}{4}}} $\\ | | | \\ 51. (2.079 Сканави) | \\ $\left(\sqrt{\sqrt{m}-\sqrt{\dfrac{m^2-9}{m}}}+\sqrt{\sqrt{m}+\sqrt{\dfrac{m^2-9}{m}}}\right)^2\sqrt{\sqrt{\dfrac{m^2}{4}}} $\\ | |
| \\ 52. (2.081 Сканави) | \\ $\sqrt{\dfrac{t\sqrt{t+2}}{\sqrt{t-2}}-\dfrac{2\sqrt{t-2}}{\sqrt{t+2}}-\dfrac{4t}{\sqrt{t^2-4}}}:\sqrt{\sqrt{t^2-4}} $\\ | | | \\ 52. (2.081 Сканави) | \\ $\sqrt{\dfrac{t\sqrt{t+2}}{\sqrt{t-2}}-\dfrac{2\sqrt{t-2}}{\sqrt{t+2}}-\dfrac{4t}{\sqrt{t^2-4}}}:\sqrt{\sqrt{t^2-4}} $\\ | |
| \\ 53. (2.085 Сканави) | \\ $\left(\dfrac{a\sqrt{a}+b\sqrt{b}}{\sqrt{a}+\sqrt{b}}-\sqrt{ab}\right)\left(\dfrac{\sqrt{a}+\sqrt{b}}{a-b}\right)^2 $\\ | | | \\ 53. (2.085 Сканави) | \\ $\left(\dfrac{a\sqrt{a}+b\sqrt{b}}{\sqrt{a}+\sqrt{b}}-\sqrt{ab}\right)\left(\dfrac{\sqrt{a}+\sqrt{b}}{a-b}\right)^2 $\\ | |
| \\ 54. (2.086 Сканави) | \\ $\left(\dfrac{a-\sqrt{a^2-b^2}}{a+\sqrt{a^2-b^2}}-\dfrac{a+\sqrt{a^2-b^2}}{a-\sqrt{a^2-b^2}}\right):\dfrac{4\sqrt{a^4-a^2b^2}}{5b^2} $\\ | | | \\ 54. (2.086 Сканави) | \\ $\left(\dfrac{a-\sqrt{a^2-b^2}}{a+\sqrt{a^2-b^2}}-\dfrac{a+\sqrt{a^2-b^2}}{a-\sqrt{a^2-b^2}}\right):\dfrac{4\sqrt{a^4-a^2b^2}}{(5b)^2} $\\ | |
| \\ 55. (2.088 Сканави) | \\ $\left(\sqrt{1-x^2}+1\right):\left(\dfrac{1}{\sqrt{x+1}}+\sqrt{x-1}\right) $\\ | | | \\ 55. (2.088 Сканави) | \\ $\left(\sqrt{1-x^2}+1\right):\left(\dfrac{1}{\sqrt{x+1}}+\sqrt{1-x}\right) $\\ | |
| \\ 56. (2.090 Сканави) | \\ $\dfrac{\dfrac{(a-b)^3}{(\sqrt{a}+\sqrt{b})^3}+2a\sqrt{a}+b\sqrt{b}}{a\sqrt{a}+b\sqrt{b}}+\dfrac{3(\sqrt{ab}-b)}{a-b} $\\ | | | \\ 56. (2.090 Сканави) | \\ $\dfrac{\dfrac{(a-b)^3}{(\sqrt{a}+\sqrt{b})^3}+2a\sqrt{a}+b\sqrt{b}}{a\sqrt{a}+b\sqrt{b}}+\dfrac{3(\sqrt{ab}-b)}{a-b} $\\ | |
| \\ 57. (2.093 Сканави) | \\ $\left(\dfrac{\sqrt{3}+1}{1+\sqrt{3}+\sqrt{t}}+\dfrac{\sqrt{3}-1}{1-\sqrt{3}+\sqrt{t}}\right)\left(\sqrt{t}-\dfrac{2}{\sqrt{t}}+2\right) $\\ | | | \\ 57. (2.093 Сканави) | \\ $\left(\dfrac{\sqrt{3}+1}{1+\sqrt{3}+\sqrt{t}}+\dfrac{\sqrt{3}-1}{1-\sqrt{3}+\sqrt{t}}\right)\left(\sqrt{t}-\dfrac{2}{\sqrt{t}}+2\right) $\\ | |