| Предыдущая версия справа и слеваПредыдущая версия | |
| math-public:up_s_b_bez_otvetov [2020/01/17 11:52] – labreslav | math-public:up_s_b_bez_otvetov [2020/01/17 12:22] (текущий) – labreslav |
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| | \\ 47. (2.046 Сканави) | \\ $\dfrac{\sqrt{1-x^2}-1}{x}\left(\dfrac{1-x}{\sqrt{1-x^2}+x-1}+\dfrac{\sqrt{1+x}}{\sqrt{1+x}-\sqrt{1-x}}\right) $\\ | | | \\ 47. (2.046 Сканави) | \\ $\dfrac{\sqrt{1-x^2}-1}{x}\left(\dfrac{1-x}{\sqrt{1-x^2}+x-1}+\dfrac{\sqrt{1+x}}{\sqrt{1+x}-\sqrt{1-x}}\right) $\\ | |
| | \\ 48. (2.052 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-x^2}}+1+\dfrac{1}{\dfrac{1}{\sqrt{1-x^2}}-1}\right)^{-2}:(2-x^2-2\sqrt{1-x^2}) $\\ | | | \\ 48. (2.052 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-x^2}}+1+\dfrac{1}{\dfrac{1}{\sqrt{1-x^2}}-1}\right)^{-2}:(2-x^2-2\sqrt{1-x^2}) $\\ | |
| | \\ 49. (2.053 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-p^2}}-\sqrt{1+p^2}\right)^2+\dfrac{2}{\sqrt{1-p^4}} $\\ | | | \\ 49. (2.053 Сканави) | \\ $\left(\dfrac{1}{\sqrt{1-p^2}}-\dfrac{1}{\sqrt{1+p^2}}\right)^2+\dfrac{2}{\sqrt{1-p^4}} $\\ | |
| | \\ 50. (2.071 Сканави) | \\ $\dfrac{(m-1)\sqrt{m}-(n-1)\sqrt{n}}{\sqrt{m^3n}+mn+m^2-m} $\\ | | | \\ 50. (2.071 Сканави) | \\ $\dfrac{(m-1)\sqrt{m}-(n-1)\sqrt{n}}{\sqrt{m^3n}+mn+m^2-m} $\\ | |
| | \\ 51. (2.079 Сканави) | \\ $\left(\sqrt{\sqrt{m}-\sqrt{\dfrac{m^2-9}{m}}}+\sqrt{\sqrt{m}+\sqrt{\dfrac{m^2-9}{m}}}\right)^2\sqrt{\sqrt{\dfrac{m^2}{4}}} $\\ | | | \\ 51. (2.079 Сканави) | \\ $\left(\sqrt{\sqrt{m}-\sqrt{\dfrac{m^2-9}{m}}}+\sqrt{\sqrt{m}+\sqrt{\dfrac{m^2-9}{m}}}\right)^2\sqrt{\sqrt{\dfrac{m^2}{4}}} $\\ | |
| | \\ 61. (2.101 Сканави) | \\ $\left(\dfrac{1}{a+\sqrt{2}}-\dfrac{a^2+4}{a^3+2\sqrt{2}}\right):\left(\dfrac{a}{2}-\dfrac{1}{\sqrt{2}}+\dfrac{1}{a}\right)^{-1} $\\ | | | \\ 61. (2.101 Сканави) | \\ $\left(\dfrac{1}{a+\sqrt{2}}-\dfrac{a^2+4}{a^3+2\sqrt{2}}\right):\left(\dfrac{a}{2}-\dfrac{1}{\sqrt{2}}+\dfrac{1}{a}\right)^{-1} $\\ | |
| | \\ 62. (2.103 Сканави) | \\ $(\sqrt{ab}-ab(a+\sqrt{ab})^{-1}):(2(\sqrt{ab}-b)(a-b)^{-1}) $\\ | | | \\ 62. (2.103 Сканави) | \\ $(\sqrt{ab}-ab(a+\sqrt{ab})^{-1}):(2(\sqrt{ab}-b)(a-b)^{-1}) $\\ | |
| | \\ 63. (2.105 Сканави) | \\ $\left(\dfrac{1+\sqrt{1-x}}{1-x+\sqrt{1-x}}+\dfrac{1-\sqrt{1+x}}{1+x-\sqrt{1+x}}\right)^2\cdot\dfrac{x^2-1}{2}+\sqrt{1-x^2} $\\ | | | \\ 63. (2.105 Сканави) | \\ $\left(\dfrac{1+\sqrt{1-x}}{1-x+\sqrt{1-x}}+\dfrac{1-\sqrt{1+x}}{1+x-\sqrt{1+x}}\right)^2\cdot\dfrac{x^2-1}{2}-\sqrt{1-x^2} $\\ | |
| | \\ 64. (2.110 Сканави) | \\ $\dfrac{\sqrt{c-d}}{c^2\sqrt{2c}}\cdot\left(\sqrt{\dfrac{c-d}{c+d}}+\sqrt{\dfrac{c^2+cd}{c^2-cd}}\right)$ , при $c=2, d=\dfrac{1}{4} $\\ | | | \\ 64. (2.110 Сканави) | \\ $\dfrac{\sqrt{c-d}}{c^2\sqrt{2c}}\cdot\left(\sqrt{\dfrac{c-d}{c+d}}+\sqrt{\dfrac{c^2+cd}{c^2-cd}}\right)$ , при $c=2, d=\dfrac{1}{4} $\\ | |
| | \\ 65. (2.115 Сканави) | \\ $4ab+\dfrac{\left(1+\left(\dfrac{a}{b}\right)^{-3}\right)a^3}{(\sqrt{a}+\sqrt{b})^2-2\sqrt{ab}}-\dfrac{\left(\dfrac{\sqrt{a}+\sqrt{b}}{2b\sqrt{a}}\right)^{-1}+\left(\dfrac{\sqrt{a}+\sqrt{b}}{2a\sqrt{b}}\right)^{-1}}{\left(\dfrac{a+\sqrt{ab}}{2}\right)^{-1}+\left(\dfrac{b+\sqrt{ab}}{2}\right)^{-1}} $\\ | | | \\ 65. (2.115 Сканави) | \\ $4ab+\dfrac{\left(1+\left(\dfrac{a}{b}\right)^{-3}\right)a^3}{(\sqrt{a}+\sqrt{b})^2-2\sqrt{ab}}-\dfrac{\left(\dfrac{\sqrt{a}+\sqrt{b}}{2b\sqrt{a}}\right)^{-1}+\left(\dfrac{\sqrt{a}+\sqrt{b}}{2a\sqrt{b}}\right)^{-1}}{\left(\dfrac{a+\sqrt{ab}}{2}\right)^{-1}+\left(\dfrac{b+\sqrt{ab}}{2}\right)^{-1}} $\\ | |
| | \\ 69. (2.145 Сканави) | \\ $\dfrac{1-ax}{1+ax}\sqrt{\dfrac{1+bx}{1-bx}}$ , при $x=\dfrac{1}{a}\sqrt{\dfrac{2a-b}{b}}; 0<\dfrac{b}{2}<a<b $\\ | | | \\ 69. (2.145 Сканави) | \\ $\dfrac{1-ax}{1+ax}\sqrt{\dfrac{1+bx}{1-bx}}$ , при $x=\dfrac{1}{a}\sqrt{\dfrac{2a-b}{b}}; 0<\dfrac{b}{2}<a<b $\\ | |
| | \\ 70. (2.203 Сканави) | \\ $\dfrac{(2x+\sqrt{x^2-1})\cdot\sqrt{\sqrt{\dfrac{x-1}{x+1}}+\sqrt{\dfrac{x+1}{x-1}}-2}}{(x+1)\sqrt{x+1}-(x-1)\sqrt{x-1}} $\\ | | | \\ 70. (2.203 Сканави) | \\ $\dfrac{(2x+\sqrt{x^2-1})\cdot\sqrt{\sqrt{\dfrac{x-1}{x+1}}+\sqrt{\dfrac{x+1}{x-1}}-2}}{(x+1)\sqrt{x+1}-(x-1)\sqrt{x-1}} $\\ | |
| | \\ 71. (2.210 Сканави) | \\ $\dfrac{2\sqrt{\dfrac{1}{4}\left(\dfrac{1}{\sqrt{a}}+\sqrt{a}\right)^2-1}}{2\sqrt{\dfrac{1}{4}\left(\dfrac{1}{\sqrt{a}}+\sqrt{a}\right)^2}-1-\dfrac{1}{2}\left(\sqrt{\dfrac{1}{a}-\sqrt{a}}\right)} $\\ | | | \\ 71. (2.210 Сканави) | \\ $\dfrac{2\sqrt{\dfrac{1}{4}\left(\dfrac{1}{\sqrt{a}}+\sqrt{a}\right)^2-1}}{2\sqrt{\dfrac{1}{4}\left(\dfrac{1}{\sqrt{a}}+\sqrt{a}\right)^2-1}-\dfrac{1}{2}\left(\sqrt{\dfrac{1}{a}-\sqrt{a}}\right)} $\\ | |
| | \\ 72. (2.216 Сканави) | \\ $\left(\sqrt{\dfrac{m+2}{m-2}}+\sqrt{\dfrac{m-2}{m+2}}\right):\left(\sqrt{\dfrac{m+2}{m-2}}-\sqrt{\dfrac{m-2}{m+2}}\right) $\\ | | | \\ 72. (2.216 Сканави) | \\ $\left(\sqrt{\dfrac{m+2}{m-2}}+\sqrt{\dfrac{m-2}{m+2}}\right):\left(\sqrt{\dfrac{m+2}{m-2}}-\sqrt{\dfrac{m-2}{m+2}}\right) $\\ | |
| | \\ 73. (2.218 Сканави) | \\ $\sqrt{x+2\sqrt{2x-4}}+\sqrt{x-2\sqrt{2x-4}} $\\ | | | \\ 73. (2.218 Сканави) | \\ $\sqrt{x+2\sqrt{2x-4}}+\sqrt{x-2\sqrt{2x-4}} $\\ | |
